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PostPosted: Mon Mar 06, 2017 11:14 am 
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Joined: Mon Mar 06, 2017 10:59 am
Posts: 1
Hi
I wonder how I am supposed to interpret the data from the transient recorder (EDU09). What I have is a 1.6 V DC input and when I save a file it looks like this:
##############
START: 2017-03-06 11:01:08
STOP : 2017-03-06 11:01:23

TIME STEP:
2 = 20ms

VOLTAGE STEP:
CH1: 32 = 0.5V
CH2: 32 = 1V

N CH1 CH2

1 227 227
2 228 228
3 228 228
4 228 228
5 228 228
6 228 228
7 228 228
###########
What I though would be the case can't really be true:
(0.5/32)*227=3.6 V


// Thanks!


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PostPosted: Mon Mar 06, 2017 5:07 pm 
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Joined: Mon Dec 11, 2006 12:03 pm
Posts: 4853
Location: Belgium
The saved data corresponds to the trace position on the screen.
The values are 0...255 corresponding to the trace position

Normally the zero level is in the middle of the screen.
This corresponds to the saved value 128.

After connecting the 1.6V DC to the input you got value 227.
The trace "movement" was 227 - 128 = 99
To calculate the voltage:

V = (0.5/32)*99=1.55 V


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